From aaa0a82b749817c751fa2287b1bc92a1a168417f Mon Sep 17 00:00:00 2001
From: janEbert <janpublicebert@posteo.net>
Date: Thu, 24 Oct 2019 22:35:59 +0200
Subject: [PATCH] Slight modifications in `recurrent` docstrings

---
 src/layers/recurrent.jl | 19 ++++++++++---------
 1 file changed, 10 insertions(+), 9 deletions(-)

diff --git a/src/layers/recurrent.jl b/src/layers/recurrent.jl
index 05466b31..d9de9884 100644
--- a/src/layers/recurrent.jl
+++ b/src/layers/recurrent.jl
@@ -15,13 +15,13 @@ in the background. `cell` should be a model of the form:
 For example, here's a recurrent network that keeps a running total of its inputs:
 
 ```julia
-accum(h, x) = (h+x, x)
+accum(h, x) = (h + x, x)
 rnn = Flux.Recur(accum, 0)
-rnn(2) # 2
-rnn(3) # 3
-rnn.state # 5
-rnn.(1:10) # apply to a sequence
-rnn.state # 60
+rnn(2)      # 2
+rnn(3)      # 3
+rnn.state   # 5
+rnn.(1:10)  # apply to a sequence
+rnn.state   # 60
 ```
 """
 mutable struct Recur{T}
@@ -47,9 +47,10 @@ Base.show(io::IO, m::Recur) = print(io, "Recur(", m.cell, ")")
 
 Reset the hidden state of a recurrent layer back to its original value.
 
-Assuming you have a `Recur` layer `rnn`, this is roughly equivalent to
-
-    rnn.state = hidden(rnn.cell)
+Assuming you have a `Recur` layer `rnn`, this is roughly equivalent to:
+```
+rnn.state = hidden(rnn.cell)
+```
 """
 reset!(m::Recur) = (m.state = m.init)
 reset!(m) = foreach(reset!, functor(m)[1])